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In case you want to replace multiple occurrences of the searchedObj you can use a classic for loop: for(let i = 0 i < myArray.

Please note that both of the above examples assume that you have only one instance of the searchedObj in myArray. Find and replace multiple occurrences of the same object in an array If we have a homogeneous object structure of the array we can just compare the elements in the array based on a specific field: const myArray = [Ĭonst searchedObj = Ĭonst i = myArray.findIndex(x => deepEqual(x, searchedObj)) Find and replace an object in an array with the same structure

📚 The unshift() method adds one or more elements to the beginning of an array and returns the new length of the array. add the item to the 1st position using unshift().deleteCount = 1 = number of elements in the array to remove from start 📚 The splice() method changes the contents of an array by removing or replacing existing elements and/or adding new elements in place. might want to traverse an array until you find either a specific element. remove the item in that specific position using splice() In JavaScript, an array can be created using formal object notation, or it.findIndex ( el => el = itemToFind ) // -> foundIdx = 3 📚 The findIndex() method returns the index of the first element in the array that satisfies the provided testing function. If you need to find the index of a value, use indexOf (). Try it If you need the index of the found element in the array, use findIndex (). If no values satisfy the testing function, undefined is returned. get the index of the founded item using findIndex() The find () method returns the first element in the provided array that satisfies the provided testing function.To find an element into an array and move to be the first, you have to: Let me know if you know a better way to do it 💪🏻 Surely there are several way to do it, this is just one of them.